Asked by lucylu
Determine the equilibrium constant, Keq, for the reaction
5.3 10–19
18.30
1.7 1054
1.9 1018
5.7 10–55
i have tried this but get the wrong answer. i have the half-rxn and fugured out E=0.536. then used eq
dG=-nFE, followed by dG=-RTInK. PLS HELP
5.3 10–19
18.30
1.7 1054
1.9 1018
5.7 10–55
i have tried this but get the wrong answer. i have the half-rxn and fugured out E=0.536. then used eq
dG=-nFE, followed by dG=-RTInK. PLS HELP
Answers
Answered by
DrBob222
I responded to this recently by saying you needed to clarify what these numbers are. I have no idea what they mean. That may explain why no one has answered you because no one can figure out to what these numbers refer.
Answered by
lucylu
right then, numbers are-
Br2 + 2e- = 2Br E=1.065V
I2(s)+ 2e- = 2I- E=0.536V
i have placed both these numbers into eq- Ecell= Ered(cathode)-Ered(anode)
but for every combination, using the before mentioned eq, i cannot get any answers that they offer.
If E i get either +/- 1.601 or +/- 0.529. these put into eq 2- dG=-nFE (n=moles, F-96485, E=? Above)
then putting that into eq 3- dG=-RTInK (with R=8.314, and T=298) to find K. I just cant get their answers!?
Br2 + 2e- = 2Br E=1.065V
I2(s)+ 2e- = 2I- E=0.536V
i have placed both these numbers into eq- Ecell= Ered(cathode)-Ered(anode)
but for every combination, using the before mentioned eq, i cannot get any answers that they offer.
If E i get either +/- 1.601 or +/- 0.529. these put into eq 2- dG=-nFE (n=moles, F-96485, E=? Above)
then putting that into eq 3- dG=-RTInK (with R=8.314, and T=298) to find K. I just cant get their answers!?
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