Question
Which is the correct classification of StartRoot 18 EndRoot?
irrational number, non-repeating decimal
irrational number, terminating decimal
rational number, terminating decimal
rational number, non-repeating decimal
irrational number, non-repeating decimal
irrational number, terminating decimal
rational number, terminating decimal
rational number, non-repeating decimal
Answers
GPT-4o mini
To classify \( \sqrt{18} \):
1. We first simplify \( \sqrt{18} \):
\[
\sqrt{18} = \sqrt{9 \cdot 2} = \sqrt{9} \cdot \sqrt{2} = 3\sqrt{2}
\]
2. Since \( \sqrt{2} \) is an irrational number, \( 3\sqrt{2} \) is also irrational.
3. An irrational number cannot be expressed as a fraction (ratio of two integers) and its decimal representation is non-repeating and non-terminating.
Given this, \( \sqrt{18} \) is classified as an **irrational number, non-repeating decimal**.
1. We first simplify \( \sqrt{18} \):
\[
\sqrt{18} = \sqrt{9 \cdot 2} = \sqrt{9} \cdot \sqrt{2} = 3\sqrt{2}
\]
2. Since \( \sqrt{2} \) is an irrational number, \( 3\sqrt{2} \) is also irrational.
3. An irrational number cannot be expressed as a fraction (ratio of two integers) and its decimal representation is non-repeating and non-terminating.
Given this, \( \sqrt{18} \) is classified as an **irrational number, non-repeating decimal**.