Question

Find the area of the figure.
Hint: Separate into regular shapes and combine the areas!
Shapes: Triangle and Rectangle
Triangle: 6 in
Rectangle: 6 in and 11 in
A = [ ? ] in²
Area Formulas: B x H or B x H/2

Answer 1

To find the total area of the figure, we'll calculate the area of the triangle and the area of the rectangle separately, and then combine them.

**Area of the Triangle:**
The formula for the area of a triangle is:
\[
\text{Area of Triangle} = \frac{B \times H}{2}
\]
Here, \( B \) (the base) is given as 6 inches, and \( H \) is the height (also 6 inches).

Substituting in the values:
\[
\text{Area of Triangle} = \frac{6 \times 6}{2} = \frac{36}{2} = 18 \text{ in}^2
\]

**Area of the Rectangle:**
The formula for the area of a rectangle is:
\[
\text{Area of Rectangle} = B \times H
\]
Here, \( B \) is 11 inches and \( H \) is 6 inches.

Substituting in the values:
\[
\text{Area of Rectangle} = 11 \times 6 = 66 \text{ in}^2
\]

**Total Area:**
Now we add the areas of the triangle and rectangle together:
\[
\text{Total Area} = \text{Area of Triangle} + \text{Area of Rectangle}
\]
\[
\text{Total Area} = 18 \text{ in}^2 + 66 \text{ in}^2 = 84 \text{ in}^2
\]

Thus, the total area of the figure is:
\[
A = 84 \text{ in}^2
\]