Find the area of the figure.

Hint: Separate into regular shapes and combine the areas!
Shapes: Triangle and Rectangle
Triangle: 6 in
Rectangle: 6 in and 11 in
A = [ ? ] in²
Area Formulas: B x H or B x H/2

1 answer

To find the total area of the figure, we'll calculate the area of the triangle and the area of the rectangle separately, and then combine them.

Area of the Triangle: The formula for the area of a triangle is: \[ \text{Area of Triangle} = \frac{B \times H}{2} \] Here, \( B \) (the base) is given as 6 inches, and \( H \) is the height (also 6 inches).

Substituting in the values: \[ \text{Area of Triangle} = \frac{6 \times 6}{2} = \frac{36}{2} = 18 \text{ in}^2 \]

Area of the Rectangle: The formula for the area of a rectangle is: \[ \text{Area of Rectangle} = B \times H \] Here, \( B \) is 11 inches and \( H \) is 6 inches.

Substituting in the values: \[ \text{Area of Rectangle} = 11 \times 6 = 66 \text{ in}^2 \]

Total Area: Now we add the areas of the triangle and rectangle together: \[ \text{Total Area} = \text{Area of Triangle} + \text{Area of Rectangle} \] \[ \text{Total Area} = 18 \text{ in}^2 + 66 \text{ in}^2 = 84 \text{ in}^2 \]

Thus, the total area of the figure is: \[ A = 84 \text{ in}^2 \]