To find the total area of the figure composed of the three rectangles, we can use the area formula for rectangles, which is:
\[ \text{Area} = \text{Base} \times \text{Height} \]
Let’s calculate the area of each rectangle:
-
Rectangle 1:
- Base = 16 inches
- Height = 8 inches
- Area = \( 16 , \text{in} \times 8 , \text{in} = 128 , \text{in}^2 \)
-
Rectangle 2:
- Base = 16 inches
- Height = 8 inches
- Area = \( 16 , \text{in} \times 8 , \text{in} = 128 , \text{in}^2 \)
-
Rectangle 3:
- Base = 8 inches
- Height = 16 inches
- Area = \( 8 , \text{in} \times 16 , \text{in} = 128 , \text{in}^2 \)
Now, we sum the areas of all three rectangles:
\[ \text{Total Area} = \text{Area of Rectangle 1} + \text{Area of Rectangle 2} + \text{Area of Rectangle 3} \]
\[ \text{Total Area} = 128 , \text{in}^2 + 128 , \text{in}^2 + 128 , \text{in}^2 = 384 , \text{in}^2 \]
Thus, the area of the figure is:
\[ A = [384] , \text{in}^2 \]