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Find the area of the figure. Hint: Separate into regular shapes and combine the areas! Shapes: 3 Rectangle Rectangle 1: 16 in a...Asked by FeelynnAsksAQuestion
                Find the area of the figure.
Hint: Separate into regular shapes and combine the areas!
Shapes: 3 Rectangle
Rectangle 1: 16 in and 8 in
Rectangle 2: 16 in and 8 in
Rectangle 3: 8 in, 16 in and 8 in
A = [ ? ] in²
Area Formulas: B x H
            
        Hint: Separate into regular shapes and combine the areas!
Shapes: 3 Rectangle
Rectangle 1: 16 in and 8 in
Rectangle 2: 16 in and 8 in
Rectangle 3: 8 in, 16 in and 8 in
A = [ ? ] in²
Area Formulas: B x H
Answers
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                    Answered by
            GPT-4o mini
            
    To find the total area of the figure composed of the three rectangles, we can use the area formula for rectangles, which is:
\[
\text{Area} = \text{Base} \times \text{Height}
\]
Let’s calculate the area of each rectangle:
1. **Rectangle 1:**
- Base = 16 inches
- Height = 8 inches
- Area = \( 16 \, \text{in} \times 8 \, \text{in} = 128 \, \text{in}^2 \)
2. **Rectangle 2:**
- Base = 16 inches
- Height = 8 inches
- Area = \( 16 \, \text{in} \times 8 \, \text{in} = 128 \, \text{in}^2 \)
3. **Rectangle 3:**
- Base = 8 inches
- Height = 16 inches
- Area = \( 8 \, \text{in} \times 16 \, \text{in} = 128 \, \text{in}^2 \)
Now, we sum the areas of all three rectangles:
\[
\text{Total Area} = \text{Area of Rectangle 1} + \text{Area of Rectangle 2} + \text{Area of Rectangle 3}
\]
\[
\text{Total Area} = 128 \, \text{in}^2 + 128 \, \text{in}^2 + 128 \, \text{in}^2 = 384 \, \text{in}^2
\]
Thus, the area of the figure is:
\[
A = [384] \, \text{in}^2
\]
    
\[
\text{Area} = \text{Base} \times \text{Height}
\]
Let’s calculate the area of each rectangle:
1. **Rectangle 1:**
- Base = 16 inches
- Height = 8 inches
- Area = \( 16 \, \text{in} \times 8 \, \text{in} = 128 \, \text{in}^2 \)
2. **Rectangle 2:**
- Base = 16 inches
- Height = 8 inches
- Area = \( 16 \, \text{in} \times 8 \, \text{in} = 128 \, \text{in}^2 \)
3. **Rectangle 3:**
- Base = 8 inches
- Height = 16 inches
- Area = \( 8 \, \text{in} \times 16 \, \text{in} = 128 \, \text{in}^2 \)
Now, we sum the areas of all three rectangles:
\[
\text{Total Area} = \text{Area of Rectangle 1} + \text{Area of Rectangle 2} + \text{Area of Rectangle 3}
\]
\[
\text{Total Area} = 128 \, \text{in}^2 + 128 \, \text{in}^2 + 128 \, \text{in}^2 = 384 \, \text{in}^2
\]
Thus, the area of the figure is:
\[
A = [384] \, \text{in}^2
\]
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