To find the area of the figure made up of three rectangles, we can calculate the area of each rectangle separately and then combine the areas.
Rectangle 1:
- Dimensions: 16 in x 8 in
- Area: \( A_1 = B \times H = 16 , \text{in} \times 8 , \text{in} = 128 , \text{in}^2 \)
Rectangle 2:
- Dimensions: 16 in x 8 in
- Area: \( A_2 = B \times H = 16 , \text{in} \times 8 , \text{in} = 128 , \text{in}^2 \)
Rectangle 3:
- Dimensions: 8 in x 16 in (it appears this is the same as 16 in x 8 in)
- Area: \( A_3 = B \times H = 8 , \text{in} \times 16 , \text{in} = 128 , \text{in}^2 \)
Total Area:
Now, we combine the areas of the three rectangles:
\[ A_{\text{total}} = A_1 + A_2 + A_3 = 128 , \text{in}^2 + 128 , \text{in}^2 + 128 , \text{in}^2 = 384 , \text{in}^2 \]
Convert to m²:
To convert from square inches to square meters, we use the conversion factor: \(1 , \text{in}^2 = 0.00064516 , \text{m}^2\)
Thus,
\[ A_{\text{total}} = 384 , \text{in}^2 \times 0.00064516 , \text{m}^2/\text{in}^2 = 0.247 , \text{m}^2 \]
Final Answer:
The area of the figure is approximately: \[ A = [0.247] , \text{m}^2 \]