Question

Find the area of the figure. Hint: Separate into regular shapes and combine the areas!
Shapes: Square and Triangle
Square: 8 in and 8 in
Triangle: 8 in
A = [ ? ] in²
Area Formulas: B x H and B x H/2

Answer 1

To find the area of the given figure, we will separate it into the two regular shapes: a square and a triangle.

1. **Area of the Square**:
A square has a formula for area given by:
\[
A = \text{side} \times \text{side}
\]
For the square with side length of 8 inches:
\[
A_{\text{square}} = 8 \, \text{in} \times 8 \, \text{in} = 64 \, \text{in}^2
\]

2. **Area of the Triangle**:
The area of a triangle is calculated using the formula:
\[
A = \frac{1}{2} \times \text{base} \times \text{height}
\]
If we assume that the triangle has a base of 8 inches and a height of 8 inches:
\[
A_{\text{triangle}} = \frac{1}{2} \times 8 \, \text{in} \times 8 \, \text{in} = \frac{1}{2} \times 64 \, \text{in}^2 = 32 \, \text{in}^2
\]

3. **Total Area**:
Now, we combine the areas of the square and the triangle to find the total area:
\[
A_{\text{total}} = A_{\text{square}} + A_{\text{triangle}} = 64 \, \text{in}^2 + 32 \, \text{in}^2 = 96 \, \text{in}^2
\]

Thus, the total area of the figure is:
\[
\boxed{96} \, \text{in}^2
\]