Question
The following code segment is intended to set max equal to the maximum value among the integer variables x, y, and z. The code segment does not work as intended in all cases.
IFO
x > y
AND
max 4-
IFy > x AND
y > z
max + y
ELSE
8
~ Mark for Review
Which of the following initial values for x, y, and z can be used to show that the code segment does not work as intended?
x = 1, y = 2, z = 3
x = 1, 7 = 3, z = 2
max +
x = 2, y = 3, z = 1
x = 3, y = 2, z = 1
IFO
x > y
AND
max 4-
IFy > x AND
y > z
max + y
ELSE
8
~ Mark for Review
Which of the following initial values for x, y, and z can be used to show that the code segment does not work as intended?
x = 1, y = 2, z = 3
x = 1, 7 = 3, z = 2
max +
x = 2, y = 3, z = 1
x = 3, y = 2, z = 1
Answers
GPT-4o mini
The provided code segment appears to be a bit jumbled, but it seems to be trying to determine the maximum of three variables: `x`, `y`, and `z`. Without seeing the exact structure of the code, it is difficult to pinpoint where the errors lie. However, we can analyze the options provided.
We're looking for a set of initial values for `x`, `y`, and `z` such that the final value of `max` is not the maximum of `x`, `y`, and `z`. To determine this, let's consider the candidate values:
1. **x = 1, y = 2, z = 3**: Here, the maximum is `3`. If the code mistakenly identifies `max` as `2`, it would not work as intended.
2. **x = 1, y = 3, z = 2**: The maximum is `3`. Similarly, if `max` is set to something less than `3`, like `1` or `2`, it would not work correctly.
3. **x = 2, y = 3, z = 1**: Again, the maximum is `3`. If the code sets `max` to `2`, it fails.
4. **x = 3, y = 2, z = 1**: Here, the maximum is `3`. If `max` ends up being `2`, it also fails.
Given these scenarios, all the combinations provided have `3` as the maximum. However, to show that the code does not work as intended, we need to look for a case where the code could potentially identify a value other than the maximum as correct.
Let's consider the first combination:
- **x = 1, y = 2, z = 3**: If the code checks conditions sequentially and fails to check that `z` is greater than both `x` and `y`, it could end up not setting the max or incorrectly setting it.
In conclusion, since all scenarios lead to a max of `3`, any of them could indicate errors in the logic depending on how the code handles its conditionals. However, the one that stands out most clearly for testing against incorrect implementations would be **x = 1, y = 2, z = 3**.
This choice can demonstrate the flaw because if the conditionals do not correctly check whether `z` is the largest, it would clearly show the failure of the intended logic to identify `3` as the maximum. Thus, **x = 1, y = 2, z = 3** can be used to demonstrate that the code does not work as intended.
We're looking for a set of initial values for `x`, `y`, and `z` such that the final value of `max` is not the maximum of `x`, `y`, and `z`. To determine this, let's consider the candidate values:
1. **x = 1, y = 2, z = 3**: Here, the maximum is `3`. If the code mistakenly identifies `max` as `2`, it would not work as intended.
2. **x = 1, y = 3, z = 2**: The maximum is `3`. Similarly, if `max` is set to something less than `3`, like `1` or `2`, it would not work correctly.
3. **x = 2, y = 3, z = 1**: Again, the maximum is `3`. If the code sets `max` to `2`, it fails.
4. **x = 3, y = 2, z = 1**: Here, the maximum is `3`. If `max` ends up being `2`, it also fails.
Given these scenarios, all the combinations provided have `3` as the maximum. However, to show that the code does not work as intended, we need to look for a case where the code could potentially identify a value other than the maximum as correct.
Let's consider the first combination:
- **x = 1, y = 2, z = 3**: If the code checks conditions sequentially and fails to check that `z` is greater than both `x` and `y`, it could end up not setting the max or incorrectly setting it.
In conclusion, since all scenarios lead to a max of `3`, any of them could indicate errors in the logic depending on how the code handles its conditionals. However, the one that stands out most clearly for testing against incorrect implementations would be **x = 1, y = 2, z = 3**.
This choice can demonstrate the flaw because if the conditionals do not correctly check whether `z` is the largest, it would clearly show the failure of the intended logic to identify `3` as the maximum. Thus, **x = 1, y = 2, z = 3** can be used to demonstrate that the code does not work as intended.