Miles is looking at a bird sitting on the top of a street light. His line of sight, which is a diagonal distance to the top of the street light, is 15 feet, and he is standing 11 feet from the base of the street light. Find the angle of elevation with which he is looking at the bird. Round your answer to the nearest hundredth.

(1 point)
Responses

36.25 degrees
36.25 degrees

56.31 degrees
56.31 degrees

47.17 degrees
47.17 degrees

42.83 degrees

1 answer

To find the angle of elevation, we can use the sine function in the context of a right triangle. In this situation:

  • The opposite side is the height of the street light (which we will find using the Pythagorean theorem).
  • The adjacent side is the distance Miles is standing from the base of the street light (11 feet).
  • The hypotenuse is the line of sight to the top of the street light (15 feet).

First, we can find the height of the street light using the Pythagorean theorem:

\[ a^2 + b^2 = c^2 \]

Where:

  • \(a\) is the height of the street light (opposite side),
  • \(b\) is the distance from the base (11 feet),
  • \(c\) is the hypotenuse (15 feet).

Rearranging the equation:

\[ a^2 + 11^2 = 15^2 \] \[ a^2 + 121 = 225 \] \[ a^2 = 225 - 121 \] \[ a^2 = 104 \] \[ a = \sqrt{104} \approx 10.2 \text{ feet} \]

Now, to find the angle of elevation \(\theta\), we can use the tangent function:

\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{a}{b} = \frac{10.2}{11} \]

Now, we find the angle \(\theta\):

\[ \theta = \tan^{-1}\left(\frac{10.2}{11}\right) \]

Calculating this gives:

\[ \theta \approx \tan^{-1}(0.9273) \approx 42.83 \text{ degrees} \]

Therefore, the angle of elevation with which Miles is looking at the bird is approximately 42.83 degrees.

So the correct response is:

42.83 degrees.