A standard number cube (or die) has six faces, numbered from 1 to 6. The even numbers on a die are 2, 4, and 6, and there's also the number 5.
We need to find the probability of rolling an even number or a 5.
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The even numbers on the die are:
- 2
- 4
- 6
This gives us a total of 3 outcomes.
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There’s also the number 5, which is a single outcome that we have not counted yet.
Now, we combine these outcomes:
- Even numbers: 2, 4, 6 (3 outcomes)
- The number 5 (1 outcome)
However, there is no overlap (we can't roll an even number and a 5 at the same time).
So, the total number of favorable outcomes is: \[ 3 \text{ (even numbers)} + 1 \text{ (the number 5)} = 4 \text{ favorable outcomes} \]
The total number of possible outcomes when rolling a dice is 6.
Therefore, the probability \( P \) of rolling an even number or a 5 is: \[ P = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{4}{6} = \frac{2}{3} \]
Thus, the answer is b. 2/3.