To determine which option represents the ion formed when aluminum achieves a full valence shell, we need to know that aluminum (Al) has an atomic number of 13 and has three valence electrons in its outer shell (with the electron configuration of [Ne] 3s² 3p¹).
When aluminum forms an ion, it tends to lose these three valence electrons to attain a stable electronic configuration similar to that of the nearest noble gas (neon). When it loses three electrons, it forms a +3 ion, represented as Al³⁺.
Without seeing the specific options (A, B, C, D) you are referring to, I can conclude that the correct answer would be the one that depicts the aluminum ion as Al³⁺. If you provide the specific options, I can help you identify which one corresponds to this ion.