Question

Students used gummy bears to represent cells in the gummy bear osmosis lab. After obtaining an initial mass for each gummy bear, the gummies were soaked for 24 hours in different solutions and then dried and massed. The solutions included: distilled water, tap water, 20% sugar solution, and 40% salt solution. After 24 hours, the percent change of each gummy bear was calculated and is shown below: Distilled Water: +320% Tap Water: +200% 40% Salt Solution: -60% 20% Sugar Solution: +85% Based on the data, which gummy bear was in the salt solution and what was the tonicity of that solution? Responses A A; hypotonicA; hypotonic B B; hypertonicB; hypertonic C C; hypertonicC; hypertonic D D; hypotonic

Answers

GPT-4o mini
To analyze the results of the gummy bear osmosis lab, we look at the percent change in mass for each gummy bear in the different solutions.

1. **Distilled Water: +320%** - This indicates that the gummy bear gained a significant amount of water, meaning it was in a hypotonic solution relative to the gummy bear. The water entered the gummy bear by osmosis.

2. **Tap Water: +200%** - Similar to distilled water, this also indicates that the gummy bear gained a significant amount of water, suggesting it was also in a hypotonic solution.

3. **40% Salt Solution: -60%** - This shows that the gummy bear lost a considerable amount of mass, meaning that water left the gummy bear to balance the concentration of salt outside. This is characteristic of a hypertonic solution relative to the gummy bear.

4. **20% Sugar Solution: +85%** - This indicates that the gummy bear gained some mass, but not as much as those in the distilled or tap water. This means it is still hypotonic relative to the gummy bear, but much less so than the other hypotonic solutions.

Based on the data, the gummy bear that lost mass (the one placed in the 40% salt solution) must be the one in the hypertonic solution.

Thus, the correct response is:

**B: B; hypertonic.**