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An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 50 in increments of 10. Multiple points are plotted around a line that points downward to the right with an arrowhead on the bottom.
The line passes approximately through left parenthesis 0 comma 45 right parenthesis, left parenthesis 2 comma 25 right parenthesis, left parenthesis 3 comma 15 right parenthesis, and left parenthesis 4.5 comma 0 right parenthesis. 13 points are plotted close to the line.

Write an equation in slope-intercept form of the trend line.

(1 point)
y=
x +
Incorrect

Look at whether the trendline goes up or down. This will tell you whether the slope is positive or negative.

1 answer

To find the equation of the trend line in slope-intercept form, we need to identify the slope (m) and the y-intercept (b) from the provided points.

  1. Identify two points on the trend line:

    • Let's use the points (0, 45) and (4.5, 0).

  2. Calculate the slope (m) using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Substituting in our points: \[ m = \frac{0 - 45}{4.5 - 0} = \frac{-45}{4.5} = -10 \]

  3. Find the y-intercept (b): Since we know that at x = 0, y = 45, the y-intercept is 45. Thus, b = 45.

  4. Write the equation in slope-intercept form (y = mx + b): \[ y = -10x + 45 \]

Thus, the equation of the trend line is: \[ y = -10x + 45 \]