Compare Linear Function 1 with Linear Function 2. Which one has the lesser initial value?

Question

• Linear Function 1: Lionel's cell phone plan costs $45 per month.
• Linear Function 2: The relationship between the number of months
Ruby has had her cell phone (x) and the total cost (y) is given by
y = 40х + 60.
(1 point)
Linear Function 1 has the lesser initial value, with an initial value equal to $0 while Linear Function 2 has an initial value equal to $40.
Linear Function 1 has the lesser initial value, with an initial value equal to
• $45 while Linear Function 2 has an initial value equal to $60.
Linear Function 2 has the lesser initial value, with an initial value equal to $40 while Linear Function 1 has an initial value equal to $45.
Linear Function 1 has the lesser initial value, with an initial value equal to $O while Linear Function 2 has an initial value equal to $60.

Answer 1

To compare the initial values of the two linear functions:

1. Linear Function 1: Lionel's cell phone plan costs $45 per month. This means the cost is constant at $45, so the initial value at month 0 is $45.

2. Linear Function 2: The relationship is given by the equation \( y = 40x + 60 \). Here, the initial value (when \( x = 0 \)) can be found by plugging in 0 for \( x \):

   \[ y = 40(0) + 60 = 60 \]

So, the initial values are:

• Linear Function 1: $45
• Linear Function 2: $60

Now to compare:

• Linear Function 1 has an initial value of $45.
• Linear Function 2 has an initial value of $60.

Conclusion: Linear Function 1 has the lesser initial value, with an initial value of $45, while Linear Function 2 has an initial value of $60.

So the correct choice is: Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.