Given 2x^2=32

Question

Solve for x


(1 point)
x=±

Answer 1

To solve the equation \( 2x^2 = 32 \), follow these steps:

1. Divide both sides of the equation by 2:

\[ x^2 = \frac{32}{2} \]

\[ x^2 = 16 \]

2. Take the square root of both sides:

\[ x = \pm \sqrt{16} \]

\[ x = \pm 4 \]

So the solutions are:

\[ x = 4 \quad \text{and} \quad x = -4 \]

Thus, the final answer is:

\[ x = \pm 4 \]