Question

You may utilize your notes, course materials, and Algebra 2B reference sheet to assist you on this assignment. However, you may NOT use the internet, any website/app, AI, or anything that will do the thinking and work for you.


Express in simplest form:

b2−2b−158b+20÷24b+10


(1 point)
Responses

−(b+3)4
the fraction with numerator negative open paren b plus 3 close paren and denominator 4

(b+3)(b−5)4
the fraction with numerator open paren b plus 3 close paren times open paren b minus 5 close paren and denominator 4

(b+3)(b+5)
the fraction with numerator open paren b plus 3 close paren and denominator open paren b plus 5 close paren

(b+3)(b−5)
open paren b plus 3 close paren times open paren b minus 5 close paren
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Answers

GPT-4o mini
To simplify the expression \( \frac{b^2 - 2b - 15}{8b + 20} \div (4b + 10) \), we start with the given expression:

1. **Rewrite the division as multiplication**:
\[
\frac{b^2 - 2b - 15}{8b + 20} \times \frac{1}{4b + 10}
\]

2. **Factor the expressions**:

- For \( b^2 - 2b - 15 \):
- We need two numbers that multiply to \(-15\) and add up to \(-2\). Those numbers are \(-5\) and \(3\).
- Therefore, \( b^2 - 2b - 15 = (b - 5)(b + 3) \).

- For \( 8b + 20 \):
- We can factor out a common factor of \(4\).
- \( 8b + 20 = 4(2b + 5) \).

- For \( 4b + 10 \):
- We can factor out a common factor of \(2\).
- \( 4b + 10 = 2(2b + 5) \).

3. **Substitute the factored forms into the expression**:
\[
\frac{(b - 5)(b + 3)}{4(2b + 5)} \times \frac{1}{2(2b + 5)}
\]
This simplifies to:
\[
\frac{(b - 5)(b + 3)}{4 \cdot 2(2b + 5)(2b + 5)} = \frac{(b - 5)(b + 3)}{8(2b + 5)^2}
\]

4. **Final expression**: Since there are no common factors to cancel, the simplest form of the expression is
\[
\frac{(b - 5)(b + 3)}{8(2b + 5)^2}
\]

Since none of the given multiple-choice answers exactly matches our derived expression, the closest correct interpretation (if we focus only on the numerator) is \( (b + 3)(b - 5) \). Hence, the best answer to choose from the provided options is:

**(b+3)(b−5)**