To evaluate the function \( f(x) = 2x^2 + 3x - 5 \) at \( x = -3 \), we can substitute \(-3\) into the function:
\[ f(-3) = 2(-3)^2 + 3(-3) - 5 \]
Calculating \( (-3)^2 \):
\[ (-3)^2 = 9 \]
Now substitute back into the equation:
\[ f(-3) = 2(9) + 3(-3) - 5 \] \[ = 18 - 9 - 5 \] \[ = 18 - 9 - 5 \] \[ = 9 - 5 \] \[ = 4 \]
Therefore,
\[ f(-3) = 4 \]