To find the equation of the linear function that relates \( x \) and \( y \) based on the given points \((4, 38)\) and \((6, 58)\), we can use the slope-intercept form of a linear equation, which is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
First, we need to calculate the slope \( m \):
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Using the points \((4, 38)\) as \((x_1, y_1)\) and \((6, 58)\) as \((x_2, y_2)\):
\[ m = \frac{58 - 38}{6 - 4} = \frac{20}{2} = 10 \]
Now that we have the slope \( m = 10 \), we can use one of the points to find the y-intercept \( b \). We'll use the point \((4, 38)\):
\[ y = mx + b \]
Substituting \( y = 38 \), \( m = 10 \), and \( x = 4 \):
\[ 38 = 10(4) + b \]
\[ 38 = 40 + b \]
Solving for \( b \):
\[ b = 38 - 40 = -2 \]
Now, we can write the equation of the linear function:
\[ y = 10x - 2 \]
Thus, the correct response is:
y = 10x - 2