The formula for the volume \( V \) of a rectangular pyramid is given by:
\[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]
For a rectangular base, the base area can be calculated as:
\[ \text{Base Area} = \text{Length} \times \text{Width} \]
Given the dimensions:
- Height = 75 in.
- Width = 111 in.
- Length = 111 in.
First, calculate the base area:
\[ \text{Base Area} = 111 , \text{in.} \times 111 , \text{in.} = 12,321 , \text{in.}^2 \]
Next, calculate the volume:
\[ V = \frac{1}{3} \times 12,321 , \text{in.}^2 \times 75 , \text{in.} \]
\[ V = \frac{1}{3} \times 924,075 , \text{in.}^3 \]
\[ V = 308,025 , \text{in.}^3 \]
Thus, the volume of the pyramid-shaped tent is:
308,025 in.³ (or 308,025 in. cubed).
The best answer is:
308,025 in.³ (or 308,025 in. cubed).