Asked by tatychass
a plane is flying southwest at 155 mi/h and encounters a wind from the west at 45.0 mi/h. what is the plane velocity in respect to the ground in standard position?
Answers
Answered by
drwls
The west component of velocity is reduced becasue of the west wind to 155cos45 - 45 = 64.6 mph (relative to the ground).
The south component of speed remains 155 sin45 = 109.6 mph
The new ground speed is the hypotenuse:
sqrt[(109.6)^2 + (64.6)^2] = 127.2 mph
The south component of speed remains 155 sin45 = 109.6 mph
The new ground speed is the hypotenuse:
sqrt[(109.6)^2 + (64.6)^2] = 127.2 mph
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