And experiment involves picking a card from a selection of cards numbered 5, 10 ,and 15 in equation form what is the probability model for this experiment list the values of X in ascending order

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1 answer

To construct a probability model for the experiment of picking a card from a selection of cards numbered 5, 10, and 15, we first define the random variable \( X \) which represents the value of the card picked.

The possible values of \( X \) are:

  • \( 5 \)
  • \( 10 \)
  • \( 15 \)

In ascending order, the values of \( X \) are: \[ X = 5, 10, 15 \]

Next, let's determine the probability model \( f(x) \). Assuming that each card has an equal chance of being selected, the probabilities for each value of \( X \) can be calculated. Since there are 3 cards, and each card is picked with equal probability, the probability for each value is:

  • \( P(X = 5) = \frac{1}{3} \)
  • \( P(X = 10) = \frac{1}{3} \)
  • \( P(X = 15) = \frac{1}{3} \)

Thus, the probability model \( f(x) \) is given by:

\[ f(x) = \begin{cases} \frac{1}{3}, & \text{if } x = 5 \ \frac{1}{3}, & \text{if } x = 10 \ \frac{1}{3}, & \text{if } x = 15 \ 0, & \text{otherwise} \end{cases} \]

In a summarized form, we can write:

  • \( f(x) = \frac{1}{3} \) for \( x = 5, 10, 15 \)

So the final answer for the probability model and the values of \( X \) is:

\[ f(x) = \begin{cases} \frac{1}{3} & \text{for } x = 5 \ \frac{1}{3} & \text{for } x = 10 \ \frac{1}{3} & \text{for } x = 15 \ 0 & \text{otherwise} \end{cases} \]

where \( x = 5, 10, 15 \).