To find the volume of each snowball, we will use the formula for the volume of a sphere, which is given by:
\[ V = \frac{4}{3} \pi r^3 \]
Where \( V \) is the volume and \( r \) is the radius.
Volume of Joshua's Snowball
Joshua's snowball has a radius of \( 6 \) cm:
\[ V = \frac{4}{3} \times 3.14 \times (6)^3 \]
Calculating \( (6)^3 = 216 \):
\[ V = \frac{4}{3} \times 3.14 \times 216 \]
Now, calculating \( \frac{4}{3} \times 3.14 \):
\[ \frac{4}{3} \times 3.14 \approx 4.1867 \]
Now, we can calculate:
\[ V \approx 4.1867 \times 216 \approx 903.8372 \]
Rounding to the nearest hundredth:
\[ V \approx 903.84 \text{ cm}^3 \]
Volume of Isabella's Snowball
Isabella's snowball has a radius of \( 3 \) cm:
\[ V = \frac{4}{3} \times 3.14 \times (3)^3 \]
Calculating \( (3)^3 = 27 \):
\[ V = \frac{4}{3} \times 3.14 \times 27 \]
Calculating \( \frac{4}{3} \times 3.14 \):
\[ \frac{4}{3} \times 3.14 \approx 4.1867 \]
Now, we can calculate:
\[ V \approx 4.1867 \times 27 \approx 112.99 \]
Rounding to the nearest hundredth:
\[ V \approx 112.99 \text{ cm}^3 \]
Complete the Statement
Joshua's snowball has a volume of 903.84 cm³, while Isabella's snowball has a volume of 112.99 cm³.