To determine which fertilizer is generally more effective, we can calculate the mean and median weights for both fertilizers.
Fertilizer A: Weights (in kg)
- 27, 20, 16, 18, 22, 19, 23, 21, 17, 19
Calculating Mean for Fertilizer A:
Mean = (27 + 20 + 16 + 18 + 22 + 19 + 23 + 21 + 17 + 19) / 10
= 20.2 kg
Calculating Median for Fertilizer A:
Sorted: 16, 17, 18, 19, 19, 20, 21, 22, 23, 27
Median (average of the 5th and 6th values) = (19 + 20) / 2 = 19.5 kg
Fertilizer B: Weights (in kg)
- 28, 19, 18, 21, 24, 20, 25, 27, 29, 21
Calculating Mean for Fertilizer B:
Mean = (28 + 19 + 18 + 21 + 24 + 20 + 25 + 27 + 29 + 21) / 10
= 23.2 kg
Calculating Median for Fertilizer B:
Sorted: 18, 19, 20, 21, 21, 24, 25, 27, 28, 29
Median (average of the 5th and 6th values) = (21 + 24) / 2 = 22.5 kg
Comparing Results:
- Mean of Fertilizer A: 20.2 kg
- Median of Fertilizer A: 19.5 kg
- Mean of Fertilizer B: 23.2 kg
- Median of Fertilizer B: 22.5 kg
Since both the mean and median for Fertilizer B are higher than those for Fertilizer A, we can conclude that:
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.