To determine which statement is true, we need to calculate the mean, median, and mode for the fuel efficiency of both car companies.
Car Company A:
- Data: 35, 28, 35, 30, 31, 38, 35, 30
- Mean: (35 + 28 + 35 + 30 + 31 + 38 + 35 + 30) / 8 = 35.125 / 8 = 34.25
- Median: To find the median, we first arrange the data: 28, 30, 30, 31, 35, 35, 35, 38. The median is the average of the 4th and 5th values: (31 + 35) / 2 = 33
- Mode: The most frequently occurring value is 35.
Car Company B:
- Data: 29, 33, 36, 27, 34, 34, 34, 25
- Mean: (29 + 33 + 36 + 27 + 34 + 34 + 34 + 25) / 8 = 32.5 / 8 = 30.625
- Median: Arrange the data: 25, 27, 29, 33, 34, 34, 34, 36. The median is the average of the 4th and 5th values: (33 + 34) / 2 = 33.5
- Mode: The most frequently occurring value is 34.
Now we can compare:
-
Mean:
- Company A: 34.25
- Company B: 30.625
- Company A has a higher mean.
-
Median:
- Company A: 33
- Company B: 33.5
- Company B has a higher median.
-
Mode:
- Company A: 35
- Company B: 34
- Company A has a higher mode.
Summary of Findings:
- Mean: Company A > Company B
- Median: Company B > Company A
- Mode: Company A > Company B
Conclusion:
The only true statement from the options given is:
The cars from Company A have a higher mean highway fuel efficiency than Company B.