What is the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll?(1 point)

Responses

2
2

1
1

14
Start Fraction 1 over 4 End Fraction

1/2
start faction 1 over 2 end fraction

1 answer

To find the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll, we can break this down into two parts:

  1. Rolling an odd number: On a six-sided die, the odd numbers are 1, 3, and 5. There are 3 odd numbers out of 6 possible outcomes. Therefore, the probability of rolling an odd number on the first roll is:

    \[ P(\text{odd}) = \frac{3}{6} = \frac{1}{2} \]

  2. Rolling an even number: The even numbers on a six-sided die are 2, 4, and 6. Similar to the odd numbers, there are 3 even numbers out of 6 possible outcomes. Therefore, the probability of rolling an even number on the second roll is:

    \[ P(\text{even}) = \frac{3}{6} = \frac{1}{2} \]

Now, because the rolls are independent events, we can multiply the probabilities of these two events together to find the combined probability:

\[ P(\text{odd first roll and even second roll}) = P(\text{odd}) \times P(\text{even}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \]

Therefore, the answer is:

\[ \frac{1}{4} \]

So, the correct answer is "Start Fraction 1 over 4 End Fraction" or \( \frac{1}{4} \).