To find \((g \circ f)(x)\), which is \(g(f(x))\), we first need to evaluate \(f(x)\) and then substitute that result into \(g(x)\).
-
Calculate \(f(x)\): \[ f(x) = -3x + 5 \]
-
Substitute \(f(x)\) into \(g(x)\): \[ g(x) = 2x^2 - 11 \] So, \[ g(f(x)) = g(-3x + 5) = 2(-3x + 5)^2 - 11 \]
-
Expand \((-3x + 5)^2\): \[ (-3x + 5)^2 = (-3x)^2 + 2 \cdot (-3x) \cdot 5 + 5^2 = 9x^2 - 30x + 25 \]
-
Substitute this back into \(g(f(x))\): \[ g(f(x)) = 2(9x^2 - 30x + 25) - 11 = 18x^2 - 60x + 50 - 11 \] \[ = 18x^2 - 60x + 39 \]
Therefore, \((g \circ f)(x) = 18x^2 - 60x + 39\).
The correct response is: 18x² − 60x + 39.