To determine the number of oxygen atoms in the products of the reaction between Fe2O3 and H2SO4, we first need to identify the products of the reaction.
When iron(III) oxide (Fe2O3) reacts with sulfuric acid (H2SO4), it typically produces iron(III) sulfate (Fe2(SO4)3) and water (H2O). The balanced equation for the reaction can be written as:
\[ \text{Fe}_2\text{O}_3 + 3\text{H}_2\text{SO}_4 \rightarrow \text{Fe}_2(\text{SO}_4)_3 + 3\text{H}_2\text{O} \]
Next, we need to count the total number of oxygen atoms in the products:
-
Iron(III) sulfate (Fe2(SO4)3):
- Each sulfate ion (SO4) has 4 oxygen atoms, and there are 3 sulfate ions.
- Total oxygen from iron(III) sulfate: \( 3 \times 4 = 12 \) oxygen atoms.
-
Water (H2O):
- Each water molecule has 1 oxygen atom, and there are 3 water molecules formed in the reaction.
- Total oxygen from water: \( 3 \times 1 = 3 \) oxygen atoms.
Finally, we sum the total number of oxygen atoms in the products:
- From Fe2(SO4)3: 12 oxygen atoms
- From 3 H2O: 3 oxygen atoms
Total oxygen atoms in the products = \( 12 + 3 = 15 \).
Thus, the final answer is 15.