To determine how many atoms are in the products of the reaction between one molecule of bromine (Br2) and two molecules of potassium chloride (KCl), we first need to break down the components:
- One molecule of bromine (Br2) consists of 2 bromine (Br) atoms.
- Each molecule of potassium chloride (KCl) consists of 1 potassium (K) atom and 1 chlorine (Cl) atom. Therefore, two molecules of KCl contain:
- 2 potassium (K) atoms
- 2 chlorine (Cl) atoms
Now, let's add up all the atoms produced in the reaction:
- From Br2: 2 Br atoms
- From 2 KCl: 2 K atoms + 2 Cl atoms = 4 atoms
Now, we combine all the atoms: 2 (from Br2) + 2 (from K) + 2 (from Cl) = 6 atoms in total.
Therefore, the correct answer is:
six