Question
Gabriella is on the track team, she is headed out for practice, she wants to know the volume of her cylindrical shaped water bottle with a radius of 2 inches and height of 10 inches. What is the volume of Gabriella’s water bottle?
Use 3.14 to approximate pi (𝜋).
Use V = 𝜋r 2
h
(2 points)
Responses
120.9 in3
120.9 in3
105.32 in3
105.32 in3
62.8 in3
62.8 in3
125.6 in3
Use 3.14 to approximate pi (𝜋).
Use V = 𝜋r 2
h
(2 points)
Responses
120.9 in3
120.9 in3
105.32 in3
105.32 in3
62.8 in3
62.8 in3
125.6 in3
Answers
GPT-4o mini
To find the volume of Gabriella’s cylindrical water bottle, we can use the formula:
\[ V = \pi r^2 h \]
Given:
- Radius (r) = 2 inches
- Height (h) = 10 inches
- Approximate value of \(\pi\) = 3.14
Now we plug in the values:
\[
V = 3.14 \times (2^2) \times 10
\]
Calculating \(2^2\):
\[
2^2 = 4
\]
Now substituting back into the formula:
\[
V = 3.14 \times 4 \times 10
\]
Calculating \(4 \times 10\):
\[
4 \times 10 = 40
\]
Now:
\[
V = 3.14 \times 40
\]
Finally, calculating \(3.14 \times 40\):
\[
V = 125.6 \, \text{in}^3
\]
Thus, the volume of Gabriella’s water bottle is \(125.6 \, \text{in}^3\).
Therefore, the correct response is:
**125.6 in³**.
\[ V = \pi r^2 h \]
Given:
- Radius (r) = 2 inches
- Height (h) = 10 inches
- Approximate value of \(\pi\) = 3.14
Now we plug in the values:
\[
V = 3.14 \times (2^2) \times 10
\]
Calculating \(2^2\):
\[
2^2 = 4
\]
Now substituting back into the formula:
\[
V = 3.14 \times 4 \times 10
\]
Calculating \(4 \times 10\):
\[
4 \times 10 = 40
\]
Now:
\[
V = 3.14 \times 40
\]
Finally, calculating \(3.14 \times 40\):
\[
V = 125.6 \, \text{in}^3
\]
Thus, the volume of Gabriella’s water bottle is \(125.6 \, \text{in}^3\).
Therefore, the correct response is:
**125.6 in³**.