Question
Christina's Pizza sells pizza by the slice for lunch. Today, they sold 76 slices, including 20 slices of pepperoni pizza. What is the experimental probability that the first slice sold during lunch tomorrow will be a slice of pepperoni pizza?
Write your answer as a fraction or whole number.
P(pepperoni)=
Write your answer as a fraction or whole number.
P(pepperoni)=
Answers
GPT-4o mini
To find the experimental probability that the first slice sold during lunch tomorrow will be a slice of pepperoni pizza, we can use the formula:
\[
P(\text{pepperoni}) = \frac{\text{number of pepperoni slices sold}}{\text{total number of slices sold}}
\]
From the information given:
- Number of pepperoni slices sold = 20
- Total number of slices sold = 76
Now we can plug these values into the formula:
\[
P(\text{pepperoni}) = \frac{20}{76}
\]
We can simplify this fraction by finding the greatest common divisor (GCD) of 20 and 76. The GCD is 4.
Now, dividing both the numerator and the denominator by 4:
\[
P(\text{pepperoni}) = \frac{20 \div 4}{76 \div 4} = \frac{5}{19}
\]
So, the experimental probability that the first slice sold during lunch tomorrow will be a slice of pepperoni pizza is:
\[
P(\text{pepperoni}) = \frac{5}{19}
\]
\[
P(\text{pepperoni}) = \frac{\text{number of pepperoni slices sold}}{\text{total number of slices sold}}
\]
From the information given:
- Number of pepperoni slices sold = 20
- Total number of slices sold = 76
Now we can plug these values into the formula:
\[
P(\text{pepperoni}) = \frac{20}{76}
\]
We can simplify this fraction by finding the greatest common divisor (GCD) of 20 and 76. The GCD is 4.
Now, dividing both the numerator and the denominator by 4:
\[
P(\text{pepperoni}) = \frac{20 \div 4}{76 \div 4} = \frac{5}{19}
\]
So, the experimental probability that the first slice sold during lunch tomorrow will be a slice of pepperoni pizza is:
\[
P(\text{pepperoni}) = \frac{5}{19}
\]