Question
Restaurants often slip takeout menus under Britney's apartment door. Britney counted how many menus there were from each type of restaurant.
Chinese 2
Japanese 9
Mediterranean 1
Thai 2
Italian 6
What is the experimental probability that the next menu slipped under Britney's door will be from a Chinese restaurant?
Write your answer as a fraction or whole number.
P(Chinese)=
Chinese 2
Japanese 9
Mediterranean 1
Thai 2
Italian 6
What is the experimental probability that the next menu slipped under Britney's door will be from a Chinese restaurant?
Write your answer as a fraction or whole number.
P(Chinese)=
Answers
Answered by
GPT-4o mini
To find the experimental probability of receiving a menu from a Chinese restaurant, we need to determine the total number of menus and the number of Chinese menus.
From the data provided:
- Chinese: 2
- Japanese: 9
- Mediterranean: 1
- Thai: 2
- Italian: 6
First, we calculate the total number of menus:
\[
\text{Total Menus} = 2 + 9 + 1 + 2 + 6 = 20
\]
Next, we find the experimental probability of receiving a Chinese restaurant menu:
\[
P(\text{Chinese}) = \frac{\text{Number of Chinese Menus}}{\text{Total Menus}} = \frac{2}{20}
\]
To simplify the fraction:
\[
\frac{2}{20} = \frac{1}{10}
\]
Thus, the experimental probability that the next menu slipped under Britney's door will be from a Chinese restaurant is
\[
P(\text{Chinese}) = \frac{1}{10}
\]
From the data provided:
- Chinese: 2
- Japanese: 9
- Mediterranean: 1
- Thai: 2
- Italian: 6
First, we calculate the total number of menus:
\[
\text{Total Menus} = 2 + 9 + 1 + 2 + 6 = 20
\]
Next, we find the experimental probability of receiving a Chinese restaurant menu:
\[
P(\text{Chinese}) = \frac{\text{Number of Chinese Menus}}{\text{Total Menus}} = \frac{2}{20}
\]
To simplify the fraction:
\[
\frac{2}{20} = \frac{1}{10}
\]
Thus, the experimental probability that the next menu slipped under Britney's door will be from a Chinese restaurant is
\[
P(\text{Chinese}) = \frac{1}{10}
\]