Consider a jar that has 20 marbles. There are 4 red, 4 blue, 4 green, 4 yellow, and 4 purple marbles. What is the probability of selecting a yellow marble without replacing it and then selecting a purple marble?(1 point)

Responses

125
Start Fraction 1 over 25 End Fraction

3995
Start Fraction 39 over 95 End Fraction

495
Start Fraction 4 over 95 End Fraction

1025
Start Fraction 10 over 25 End Fraction

1 answer

To find the probability of selecting a yellow marble first and then a purple marble without replacing the first marble, we can follow these steps:

  1. Determine the total number of marbles and the number of yellow marbles.

    • Total marbles: 20
    • Yellow marbles: 4
  2. Calculate the probability of selecting a yellow marble first. \[ P(\text{yellow}) = \frac{\text{Number of yellow marbles}}{\text{Total number of marbles}} = \frac{4}{20} = \frac{1}{5} \]

  3. Now, determine the total number of marbles remaining after removing one yellow marble.

    • After selecting one yellow marble, the remaining total is \(20 - 1 = 19\) marbles.
    • The number of purple marbles is still \(4\).
  4. Calculate the probability of selecting a purple marble next. \[ P(\text{purple | yellow selected}) = \frac{\text{Number of purple marbles}}{\text{Total number of remaining marbles}} = \frac{4}{19} \]

  5. Now multiply the probabilities to find the combined probability of both events occurring. \[ P(\text{yellow and then purple}) = P(\text{yellow}) \times P(\text{purple | yellow selected}) = \frac{1}{5} \times \frac{4}{19} \]

  6. Performing the multiplication: \[ P(\text{yellow and then purple}) = \frac{1 \times 4}{5 \times 19} = \frac{4}{95} \]

Therefore, the probability of selecting a yellow marble first and then a purple marble without replacement is:

\[ \frac{4}{95} \]

So, the correct answer is: Start Fraction 4 over 95 End Fraction.