To solve this problem, we need to calculate the probabilities of the events defined.
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P(A and B): This is the probability of drawing a card that is both a red card and an ace.
- There are 2 red aces in the deck: the Ace of Hearts and the Ace of Diamonds.
- Therefore, \( P(A \text{ and } B) = \frac{\text{Number of red aces}}{\text{Total number of cards}} = \frac{2}{52} = \frac{1}{26} \).
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P(A): This is the probability of drawing a red card.
- There are a total of 26 red cards (13 diamonds and 13 hearts).
- Therefore, \( P(A) = \frac{\text{Number of red cards}}{\text{Total number of cards}} = \frac{26}{52} = \frac{1}{2} \).
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P(B): This is the probability of drawing an ace.
- There are 4 aces in the deck (one for each suit).
- Therefore, \( P(B) = \frac{\text{Number of aces}}{\text{Total number of cards}} = \frac{4}{52} = \frac{1}{13} \).
Now we state whether events A and B are independent. Events A and B are independent if \( P(A \text{ and } B) = P(A) \times P(B) \).
Now let's check this: \[ P(A) \times P(B) = \left(\frac{1}{2}\right) \times \left(\frac{1}{13}\right) = \frac{1}{26} \] Since \( P(A \text{ and } B) = \frac{1}{26} \) and \( P(A) \times P(B) = \frac{1}{26} \), it follows that the events A and B are independent.
To summarize:
- \( P(A \text{ and } B) = \frac{1}{26} \)
- \( P(A) = \frac{1}{2} \)
- \( P(B) = \frac{1}{13} \)
- Since \( P(A \text{ and } B) = P(A) \times P(B) \), events A and B are independent.
Final answers:
- P(A and B) = \( \frac{1}{26} \)
- P(A) = \( \frac{1}{2} \)
- P(B) = \( \frac{1}{13} \)
- Events A and B are independent (enter 2).