To assist you with this project, we'll first need the specific six card values that your teacher pulled from the deck in Part 1. Since that information wasn’t provided, I will create an example set of cards to illustrate the necessary calculations. Please replace my example cards with the actual cards you have for your project.
Example Set of Cards:
- 3
- 5
- 7
- 10 (Jack)
- 10 (Queen)
- 1 (Ace)
Part 1
-
Relist the cards in the correct order right here using their point values:
- Ordered Set: 1, 3, 5, 7, 10, 10
-
Find the mean of the data set and put your answer below showing your work:
- Calculation: \[ \text{Mean} = \frac{1 + 3 + 5 + 7 + 10 + 10}{6} = \frac{36}{6} = 6 \]
- Mean: 6
-
Find the median of the data set and put your answer below showing your work:
- Ordered Set: 1, 3, 5, 7, 10, 10
- Calculation: \[ \text{Median} = \frac{5 + 7}{2} = \frac{12}{2} = 6 \]
- Median: 6
-
Find the mode (which number appears the most) of the data set and put your answer below showing your work:
- Calculation: The number 10 appears most frequently (twice).
- Mode: 10
Part 2
Now take your lowest card (1) and throw it out of the set. You will replace it with a Joker card which is worth 19 points. You will still only have 6 cards total.
-
Relist the cards in the correct order right here using their point values:
- Ordered Set: 3, 5, 7, 10, 10, 19
-
Find the mean of the new data set and put your answer below showing your work:
- Calculation: \[ \text{Mean} = \frac{3 + 5 + 7 + 10 + 10 + 19}{6} = \frac{54}{6} = 9 \]
- Mean: 9
-
Find the median of the new data set and put your answer below showing your work:
- Ordered Set: 3, 5, 7, 10, 10, 19
- Calculation: \[ \text{Median} = \frac{7 + 10}{2} = \frac{17}{2} = 8.5 \]
- Median: 8.5
-
Find the mode of the new data set and put your answer below showing your work:
- Calculation: The number 10 appears most frequently (twice).
- Mode: 10
Part 3: Compare the two sets and describe. Be sure to include which one was affected the most.
-
How did the outlier (the Joker card) affect the mean?
- The mean increased from 6 to 9 after including the Joker card. The outlier shifted the average higher because it added a significant amount of value that was not present in the original set.
-
How did the outlier affect the median?
- The median decreased from 6 to 8.5. This change indicates that the outlier affected the center of the dataset, but less dramatically than it did the mean since the new median remained lower than the outlier value.
-
How did the outlier affect the mode?
- The mode remained unchanged at 10, as this value continued to appear the most frequently in both datasets.
Summary
In conclusion, the outlier (Joker card) had a more pronounced effect on the mean than on the median and did not affect the mode at all. The mean rose significantly, while the median showed a smaller increase, demonstrating the sensitivity of the mean to outliers compared to the median.
Feel free to replace the example values with your actual card values as needed!