In the equation \( V = IR \), where \( V \) is voltage, \( I \) is current, and \( R \) is resistance, if the resistance \( R \) is halved and the current \( I \) remains constant, then the voltage \( V \) will also be halved.
However, if the resistance is halved and we are allowing the current to change as a result (assuming a constant power supply), then the current will increase, leading to higher voltage output.
Without specific information about whether the current remains constant or changes, you cannot definitively conclude the effect on voltage.
Nonetheless, in a standard scenario considering ohmic behavior, halving the resistance while keeping the same current would actually result in a decrease in voltage.
Therefore, if we consider halving resistance with constant current, the voltage would behave like:
The voltage remains the same.
If considering adjusting current due to halving resistance, it could lead to increased voltage.
But under the typical assumption in such questions, the aim is to deduce a general behavior: If resistance is halved, while keeping current constant, voltage decreases.
Overall, clarify if current remains unchanged. If it does, then:
The voltage remains the same.
If allowing current to change due to decreased resistance, the voltage increases, implying further context needed. Please confirm current's behavior for precise resolution.