Question
You have sampled a population in which you know that the percentage of the homozygous recessive genotype (aa) is 36%. Using that 36%, calculate the following- the frequency of the "a" allele. (q) p2 + 2pq + q2 = 1 and p + q = 1 a 0.36 b 0.4 c 0.6 d 1
Answers
GPT-4o mini
To calculate the frequency of the "a" allele, we can use the information given about the homozygous recessive genotype (aa).
Given that the percentage of the homozygous recessive genotype (aa) is 36%, we can denote this as \( q^2 \):
\[
q^2 = 0.36
\]
We can find \( q \) (the frequency of the "a" allele) by taking the square root of \( q^2 \):
\[
q = \sqrt{0.36} = 0.6
\]
Next, we can verify our calculation using the Hardy-Weinberg principle. Since \( p + q = 1 \), we can find \( p \) (the frequency of the "A" allele):
\[
p = 1 - q = 1 - 0.6 = 0.4
\]
So, \( q \) (the frequency of the "a" allele) is **0.6**.
Based on the given options, the correct answer is:
c) 0.6
Given that the percentage of the homozygous recessive genotype (aa) is 36%, we can denote this as \( q^2 \):
\[
q^2 = 0.36
\]
We can find \( q \) (the frequency of the "a" allele) by taking the square root of \( q^2 \):
\[
q = \sqrt{0.36} = 0.6
\]
Next, we can verify our calculation using the Hardy-Weinberg principle. Since \( p + q = 1 \), we can find \( p \) (the frequency of the "A" allele):
\[
p = 1 - q = 1 - 0.6 = 0.4
\]
So, \( q \) (the frequency of the "a" allele) is **0.6**.
Based on the given options, the correct answer is:
c) 0.6