and j(x)=1.2x
. Which statement correctly describes how Liam should do this and what he will observe?(1 point)
Responses
Liam should compare the rates of change of the terms in both sequences. The growth rate of h(x)=1.2x
will quickly surpass the growth rate of j(x)=1.2x
.
Liam should compare the rates of change of the terms in both sequences. The growth rate of h left parenthesis x right parenthesis equals 1.2 x will quickly surpass the growth rate of j left parenthesis x right parenthesis equals 1.2 superscript x baseline .
Liam should look at where one sequence has terms greater than the terms in the other sequence. The growth rate of h(x)=1.2x
is greater than the growth rate of j(x)=1.2x
when its terms are greater.
Liam should look at where one sequence has terms greater than the terms in the other sequence. The growth rate of h left parenthesis x right parenthesis equals 1.2 x is greater than the growth rate of j left parenthesis x right parenthesis equals 1.2 superscript x baseline when its terms are greater.
Liam should look at where one sequence has terms greater than the terms in the other sequence. The growth rate of j(x)=1.2x
is only greater than the growth rate of h(x)=1.2x
when its terms are greater.
Liam should look at where one sequence has terms greater than the terms in the other sequence. The growth rate of j left parenthesis x right parenthesis equals 1.2 superscript x baseline is only greater than the growth rate of h left parenthesis x right parenthesis equals 1.2 x when its terms are greater.
Liam should compare the rates of change of the terms in both sequences. The growth rate of j(x)=1.2x
will quickly surpass the growth rate of h(x)=1.2x
.
1 answer
The correct statement for Liam's task is:
Liam should compare the rates of change of the terms in both sequences. The growth rate of h(x)=1.2^x will quickly surpass the growth rate of j(x)=1.2x.
This statement correctly identifies that \( h(x) = 1.2^x \) is an exponential function and will grow much faster than \( j(x) = 1.2x \), which is a linear function. Exponential growth eventually surpasses linear growth as \( x \) increases.
