To compare the initial values of Linear Function 1 and Linear Function 2, we need to identify their initial values.
Linear Function 1: Lionel’s cell phone plan costs $45 per month. This indicates that the cost starts at $45, so the initial value is $45.
Linear Function 2: The relationship is given by the equation \(y = 40x + 60\). The initial value (or y-intercept) occurs when \(x = 0\): \[ y = 40(0) + 60 = 60 \] Thus, the initial value for Linear Function 2 is $60.
Now, we can compare the two initial values:
- Initial value of Linear Function 1 = $45
- Initial value of Linear Function 2 = $60
Since $45 (Linear Function 1) is less than $60 (Linear Function 2), we conclude that:
Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.