Asked by Jess
A hockey puck moving due east with speed 1.00 m/s collides with an identical puck moving 40 degrees south of west with speed 2.00 m/s. After they collide, the first puck is moving south with speed 1.50 m/s. What is the direction and speed of the second puck?
Answers
Answered by
bobpursley
break up each puck into N, E components. Then use the law of conservation of momentum in each direction.
N:
0-M*2sin40=-M*1.5+M*Xn
notice the M's divide out. Solve for Xn, the north component of the second puck.
E:
M*1-2Mcos40=0+MXe
solve for Xe, the east component of the second puck.
N:
0-M*2sin40=-M*1.5+M*Xn
notice the M's divide out. Solve for Xn, the north component of the second puck.
E:
M*1-2Mcos40=0+MXe
solve for Xe, the east component of the second puck.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.