What is the irrational square root 28−−√

simplified?(1 point)
Responses

214−−√
2 start root 14 end root

4–√ ⋅ 7–√
start root 4 end root times start root 7 end root

27–√
2 start root 7 end root

47–√

1 answer

To simplify \(\sqrt{28}\), let's start by breaking it down:

\[ \sqrt{28} = \sqrt{4 \cdot 7} \]

Now, we can apply the property of square roots that states \(\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\):

\[ \sqrt{28} = \sqrt{4} \cdot \sqrt{7} \]

Since we know that \(\sqrt{4} = 2\), we can simplify further:

\[ \sqrt{28} = 2 \cdot \sqrt{7} \]

Thus, the simplified form of \(\sqrt{28}\) is:

\[ 2\sqrt{7} \]

Therefore, the correct response is:

2\(\sqrt{7}\).