Question

One hundred students were surveyed whether they were left-handed, right-handed, or ambidextrous (a person that can use either hand loresis with equal ease). The table shows the results of the survey.
Male
Left-Handed
Right-Handed
29
20
Ambidextrous
1
Female
16
32
2
One of the students is chosen at random.
What is the probability that the student is male, given that the student is left-handed?
• A.
29
45
O D.
45
50
OE.
29
100
B.
29
50
C.
33
50

Answer 1

To find the probability that a student is male, given that the student is left-handed, we can use the formula for conditional probability:

\[
P(\text{Male | Left-Handed}) = \frac{P(\text{Male and Left-Handed})}{P(\text{Left-Handed})}
\]

From the data provided:

- Number of left-handed males: 29
- Number of left-handed females: 16
- Total number of left-handed students: \(29 + 16 = 45\)

Now, we can plug the values into the formula:

\[
P(\text{Male | Left-Handed}) = \frac{29}{45}
\]

So the final answer is:

\[
\text{The probability that the student is male, given that the student is left-handed, is } \frac{29}{45}.
\]

None of the answer options corresponds exactly to this probability. However, note that the answer option A "29/45" appears to correspond to this calculation. Please confirm if there's a misunderstanding in the interpretation of the options. If 29 and 45 correspond to specific answer choices, then option A would be correct.