Asked by STANATEEZ
What is −72−−−−√3 simplified?
Note: You will find the option to add a cubic root symbol in the Algebra (×) keyboard.
(1 point)
Note: You will find the option to add a cubic root symbol in the Algebra (×) keyboard.
(1 point)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To simplify \( -72\sqrt{3} \), we can look for a common way to rewrite the expression or isolate terms.
First, \( -72 \) can be expressed as:
\[
-72 = -36 \times 2
\]
Thus:
\[
-72\sqrt{3} = -36\sqrt{3} \times 2
\]
Next, since we notice that \( -36 \) is a perfect square, we can rewrite it:
\[
-36 = -1 \times 36 = -1 \times 6^2
\]
This gives us:
\[
-72\sqrt{3} = -1 \times 6^2 \times 2\sqrt{3} = -6^2 \times 2\sqrt{3}
\]
However, if you meant \( -72 \) to be the cube root instead of the square root in your expression (as noted by your reference to a cubic root), we may consider \( -72 \) taking a cubic root:
The expression could imply the cubic root of -72 multiplied by \( \sqrt{3} \):
\[
\sqrt[3]{-72} \cdot \sqrt{3}
\]
The cubic root of -72 can be simplified as:
\[
\sqrt[3]{-72} = \sqrt[3]{-1 \cdot 72} = -\sqrt[3]{72}
\]
Now, finding the prime factorization of 72 we get:
\[
72 = 8 \times 9 = 2^3 \times 3^2
\]
So:
\[
\sqrt[3]{72} = \sqrt[3]{2^3 \cdot 3^2} = 2 \sqrt[3]{3^2} = 2\sqrt[3]{9}
\]
Thus, putting it all together:
\[
\sqrt[3]{-72} = -2 \sqrt[3]{9}
\]
If we multiply that by \( \sqrt{3} \):
\[
-2 \sqrt[3]{9} \cdot \sqrt{3}
\]
This expression doesn't simplify further neatly without approximating values.
If the original \( -72\sqrt{3} \) was entirely meant as is, then the answer remains:
\[
-72 \sqrt{3}
\]
If it was meant to evaluate \( \sqrt[3]{-72} \sqrt{3} \), let me know!
First, \( -72 \) can be expressed as:
\[
-72 = -36 \times 2
\]
Thus:
\[
-72\sqrt{3} = -36\sqrt{3} \times 2
\]
Next, since we notice that \( -36 \) is a perfect square, we can rewrite it:
\[
-36 = -1 \times 36 = -1 \times 6^2
\]
This gives us:
\[
-72\sqrt{3} = -1 \times 6^2 \times 2\sqrt{3} = -6^2 \times 2\sqrt{3}
\]
However, if you meant \( -72 \) to be the cube root instead of the square root in your expression (as noted by your reference to a cubic root), we may consider \( -72 \) taking a cubic root:
The expression could imply the cubic root of -72 multiplied by \( \sqrt{3} \):
\[
\sqrt[3]{-72} \cdot \sqrt{3}
\]
The cubic root of -72 can be simplified as:
\[
\sqrt[3]{-72} = \sqrt[3]{-1 \cdot 72} = -\sqrt[3]{72}
\]
Now, finding the prime factorization of 72 we get:
\[
72 = 8 \times 9 = 2^3 \times 3^2
\]
So:
\[
\sqrt[3]{72} = \sqrt[3]{2^3 \cdot 3^2} = 2 \sqrt[3]{3^2} = 2\sqrt[3]{9}
\]
Thus, putting it all together:
\[
\sqrt[3]{-72} = -2 \sqrt[3]{9}
\]
If we multiply that by \( \sqrt{3} \):
\[
-2 \sqrt[3]{9} \cdot \sqrt{3}
\]
This expression doesn't simplify further neatly without approximating values.
If the original \( -72\sqrt{3} \) was entirely meant as is, then the answer remains:
\[
-72 \sqrt{3}
\]
If it was meant to evaluate \( \sqrt[3]{-72} \sqrt{3} \), let me know!
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