Asked by Travis
Find the arc of the following: f(x)=x^2-8x+15 from x=4 to x=6
Answers
Answered by
SB
f(x)=x^2-8x+15
x=4
f(4)=(4^2)-8(4)+15
f(4)=(16)-8(4)+15
f(4)=16-32+15
f(4)=-16+15
f(4)= -1
f(x)=x^2-8x+15
x=6
f(6)=(6)^2-8(6)+15
f(6)=(36)-8(6)+15
f(6)=36-48+15
f(6)= -12+15
f(6)=3
x=4
f(4)=(4^2)-8(4)+15
f(4)=(16)-8(4)+15
f(4)=16-32+15
f(4)=-16+15
f(4)= -1
f(x)=x^2-8x+15
x=6
f(6)=(6)^2-8(6)+15
f(6)=(36)-8(6)+15
f(6)=36-48+15
f(6)= -12+15
f(6)=3
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