Question
A community swimming pool starts with 250 gallons of water. Julian starts filling the pool at a rate of 500 gallons per hour.
How many gallons are in the pool to start? In other words, how many gallons are in the pool after 0 hours?
Time in hours Gallons of water in the pool
0
1
2
3
How many gallons are in the pool to start? In other words, how many gallons are in the pool after 0 hours?
Time in hours Gallons of water in the pool
0
1
2
3
Answers
GPT-4o mini
To find the amount of water in the pool over time, you start with the initial amount of water and then add the amount filled by Julian at a rate of 500 gallons per hour. The initial amount is 250 gallons.
Here are the amounts in the pool at different time intervals:
- At **0 hours**:
\[
\text{Gallons} = 250 \text{ gallons}
\]
- At **1 hour**:
\[
\text{Gallons} = 250 + (500 \times 1) = 250 + 500 = 750 \text{ gallons}
\]
- At **2 hours**:
\[
\text{Gallons} = 250 + (500 \times 2) = 250 + 1000 = 1250 \text{ gallons}
\]
- At **3 hours**:
\[
\text{Gallons} = 250 + (500 \times 3) = 250 + 1500 = 1750 \text{ gallons}
\]
So the data table would look like this:
| Time in hours | Gallons of water in the pool |
|--------------|------------------------------|
| 0 | 250 |
| 1 | 750 |
| 2 | 1250 |
| 3 | 1750 |
Here are the amounts in the pool at different time intervals:
- At **0 hours**:
\[
\text{Gallons} = 250 \text{ gallons}
\]
- At **1 hour**:
\[
\text{Gallons} = 250 + (500 \times 1) = 250 + 500 = 750 \text{ gallons}
\]
- At **2 hours**:
\[
\text{Gallons} = 250 + (500 \times 2) = 250 + 1000 = 1250 \text{ gallons}
\]
- At **3 hours**:
\[
\text{Gallons} = 250 + (500 \times 3) = 250 + 1500 = 1750 \text{ gallons}
\]
So the data table would look like this:
| Time in hours | Gallons of water in the pool |
|--------------|------------------------------|
| 0 | 250 |
| 1 | 750 |
| 2 | 1250 |
| 3 | 1750 |