Question
A team of 17 softball players needs to choose three players to refill the water cooler. What are the number of possibilities?
(1 Point)
272
680
4,080
(1 Point)
272
680
4,080
Answers
Answered by
GPT-4o mini
To determine how many ways we can choose 3 players from a team of 17, we can use the combination formula, which is given by:
\[
C(n, r) = \frac{n!}{r!(n-r)!}
\]
Where:
- \( n \) is the total number of items (in this case, players),
- \( r \) is the number of items to choose (in this case, players to refill the cooler),
- \( ! \) denotes factorial, which is the product of all positive integers up to that number.
In this scenario, we have \( n = 17 \) and \( r = 3 \).
Substituting these values into the formula gives us:
\[
C(17, 3) = \frac{17!}{3!(17-3)!} = \frac{17!}{3! \cdot 14!}
\]
This simplifies to:
\[
C(17, 3) = \frac{17 \times 16 \times 15}{3 \times 2 \times 1}
\]
Now, calculating the numerator:
\[
17 \times 16 \times 15 = 4080
\]
And the denominator:
\[
3 \times 2 \times 1 = 6
\]
Now, we divide the numerator by the denominator:
\[
C(17, 3) = \frac{4080}{6} = 680
\]
Thus, the number of possibilities to choose 3 players from 17 is **680**.
\[
C(n, r) = \frac{n!}{r!(n-r)!}
\]
Where:
- \( n \) is the total number of items (in this case, players),
- \( r \) is the number of items to choose (in this case, players to refill the cooler),
- \( ! \) denotes factorial, which is the product of all positive integers up to that number.
In this scenario, we have \( n = 17 \) and \( r = 3 \).
Substituting these values into the formula gives us:
\[
C(17, 3) = \frac{17!}{3!(17-3)!} = \frac{17!}{3! \cdot 14!}
\]
This simplifies to:
\[
C(17, 3) = \frac{17 \times 16 \times 15}{3 \times 2 \times 1}
\]
Now, calculating the numerator:
\[
17 \times 16 \times 15 = 4080
\]
And the denominator:
\[
3 \times 2 \times 1 = 6
\]
Now, we divide the numerator by the denominator:
\[
C(17, 3) = \frac{4080}{6} = 680
\]
Thus, the number of possibilities to choose 3 players from 17 is **680**.