Question
The water level of a lake started at 60 feet. During a drought the water level dropped 6% each week. Write an exponential function that describes the water level in terms of the number of weeks.
Weeks: 0, 1, 2, 3, 4.
Water Level: 60, 56.4, 53.02, 49.84, 46.84.
Points on graph: 60, 56.4, 53.02, 49.84, 46.84.
y=_____
Weeks: 0, 1, 2, 3, 4.
Water Level: 60, 56.4, 53.02, 49.84, 46.84.
Points on graph: 60, 56.4, 53.02, 49.84, 46.84.
y=_____
Answers
GPT-4o mini
To write an exponential function that describes the water level of the lake in terms of the number of weeks, we can use the general form of an exponential decay function:
\[
y = a(1 - r)^t
\]
Where:
- \( y \) is the water level after \( t \) weeks,
- \( a \) is the initial amount (the water level at week 0),
- \( r \) is the rate of decay (as a decimal),
- \( t \) is the time in weeks.
In this case:
- The initial water level \( a = 60 \) feet,
- The decay rate \( r = 0.06 \) (since the water level drops by 6%).
Thus, the function becomes:
\[
y = 60(1 - 0.06)^t
\]
Simplifying this, we get:
\[
y = 60(0.94)^t
\]
So, the exponential function that describes the water level in terms of the number of weeks \( t \) is:
\[
y = 60(0.94)^t
\]
\[
y = a(1 - r)^t
\]
Where:
- \( y \) is the water level after \( t \) weeks,
- \( a \) is the initial amount (the water level at week 0),
- \( r \) is the rate of decay (as a decimal),
- \( t \) is the time in weeks.
In this case:
- The initial water level \( a = 60 \) feet,
- The decay rate \( r = 0.06 \) (since the water level drops by 6%).
Thus, the function becomes:
\[
y = 60(1 - 0.06)^t
\]
Simplifying this, we get:
\[
y = 60(0.94)^t
\]
So, the exponential function that describes the water level in terms of the number of weeks \( t \) is:
\[
y = 60(0.94)^t
\]