To find the probability that the sum is odd (event A) given that the sum is 6 or greater (event B), we can use the conditional probability formula:
\[ P(A | B) = \frac{P(A \cap B)}{P(B)} \]
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Identify outcomes:
- The possible sums when rolling two six-sided dice range from 2 to 12.
- The sums listed in Circle 1 (event A: "sum is odd") are 3, 5, 7, 9, and 11.
- The sums listed in Circle 2 (event B: "sum is 6 or greater") are 6, 7, 8, 9, 10, 11, and 12.
- The intersection (A ∩ B) contains the sums that are both odd and 6 or greater, which are 7, 9, and 11.
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Count outcomes:
- The favorable outcomes for \( A \cap B \) (sum is odd and 6 or greater) are 7, 9, and 11. This gives us 3 outcomes.
- The outcomes for B (sums 6 or greater) are 6, 7, 8, 9, 10, 11, and 12. This gives us 7 outcomes.
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Calculate probabilities:
- \( P(A \cap B) = \frac{3}{36} \) since there are 3 favorable outcomes out of 36 possible outcomes when rolling two dice.
- \( P(B) = \frac{7}{36} \) since there are 7 favorable outcomes out of 36 possible outcomes.
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Use the conditional probability formula: \[ P(A | B) = \frac{P(A \cap B)}{P(B)} = \frac{\frac{3}{36}}{\frac{7}{36}} = \frac{3}{7} \]
Thus, the probability that the sum is odd given that the sum is 6 or greater is:
\[ \boxed{\frac{3}{7}} \]