To determine which city has a higher median daily high temperature, we first need to calculate the median for each city's daily high temperatures.
Dayton temperatures:
77, 82, 85, 87, 90, 85, 79, 86, 91, 88
First, we will sort the Dayton temperatures in ascending order: 77, 79, 82, 85, 85, 86, 87, 88, 90, 91
Since there are 10 temperatures, the median will be the average of the 5th and 6th values:
- 5th: 85
- 6th: 86
Median for Dayton:
\[
\text{Median} = \frac{85 + 86}{2} = \frac{171}{2} = 85.5
\]
Laredo temperatures:
81, 79, 80, 86, 88, 92, 82, 88, 84, 87
Next, we will sort the Laredo temperatures in ascending order: 79, 80, 81, 82, 84, 86, 87, 88, 88, 92
Again, since there are 10 temperatures, the median will be the average of the 5th and 6th values:
- 5th: 84
- 6th: 86
Median for Laredo:
\[
\text{Median} = \frac{84 + 86}{2} = \frac{170}{2} = 85
\]
Now, we compare the two medians:
- Median for Dayton: 85.5 °F
- Median for Laredo: 85.0 °F
Difference:
\[
85.5 - 85.0 = 0.5
\]
Conclusion:
Dayton has a higher median daily high temperature than Laredo by 0.5°F.
The correct response is:
Dayton has a higher median daily high temperature than Laredo by 0.5 °F.