Question

STUDENT B IS 6'2 AND WEIGHS 210 LBS
STUDENT A IS 6 A CLAIMS THEY CAN LIFT AROUND 220
HINT!!!!!
THEY MUST CARRY STUDENT B A DISTANCE OF ABOUT 50 FT
Lifting max ≠ carrying max.

General estimate: Carrying weight over distance typically requires 60–70% of your maximum lift strength to be sustainable over short distances.

Answer 1

To estimate whether Student A can carry Student B over a distance of about 50 feet, we need to consider both their lifting capabilities and the carrying requirements.

1. **Student B's weight**: 210 lbs
2. **Student A's lift capacity**: 220 lbs

**Estimating Carrying Capability**:
According to the hint, carrying weight over a distance typically requires about 60–70% of your maximum lift strength to be sustainable for short distances.

- **60% of Student A's max lift**:
\[
0.60 \times 220 \, \text{lbs} = 132 \, \text{lbs}
\]

- **70% of Student A's max lift**:
\[
0.70 \times 220 \, \text{lbs} = 154 \, \text{lbs}
\]

This means that for Student A to carry Student B over 50 feet, Student A would need the effective carrying strength to be between 132 lbs (minimum) and 154 lbs (maximum).

### Conclusion
Since Student B weighs 210 lbs, which is significantly above Student A's carrying capacity (even at 70% of their lifting capacity), it seems that Student A would likely struggle to carry Student B for 50 feet safely and sustainably.

**Therefore, it is unlikely that Student A can carry Student B over that distance.**