On Roy’s first birthday, his grandfather placed $100 in a bank account. On Roy’s second birthday, his grandfather placed $80 in the account and continued to place $80 each passing year. The arithmetic sequence 100, 180, 260, 340,… indicates the account balance for the first four years. 1 point)

Responses

f(n)=80+(n−1)100
f left parenthesis n right parenthesis equals 80 plus left parenthesis n minus 1 right parenthesis 100

f(n)=80(100)n−1
f left parenthesis n right parenthesis equals 80 left parenthesis 100 right parenthesis superscript n minus 1 baseline

f(n)=100+80(n)
f left parenthesis n right parenthesis equals 100 plus 80 left parenthesis n right parenthesis

f(n)=100+(n−1)80

1 answer

To model the account balance for Roy after \( n \) years, we can analyze the deposits made by his grandfather:

  • On the first birthday (\( n = 1 \)), the account balance is \( 100 \).
  • On the second birthday (\( n = 2 \)), the balance is \( 100 + 80 = 180 \).
  • On the third birthday (\( n = 3 \)), the balance is \( 100 + 80 + 80 = 260 \).
  • On the fourth birthday (\( n = 4 \)), the balance is \( 100 + 80 + 80 + 80 = 340 \).

We see that the initial deposit is \( 100 \), and every subsequent year, an additional \( 80 \) is added.

Thus, the general formula for the total balance after \( n \) years can be represented as follows:

\[ f(n) = 100 + 80(n - 1) \]

This is because for every year after the first, \( 80 \) is added. The term \( (n - 1) \) accounts for the additional years after the first birthday.

So, the correct option from the given responses is:

f(n) = 100 + 80(n - 1)