k = 0.693/t1/2
Substitute k into the following:
ln(36.6/X) = kt
The only unknown is X. Solve for that.
Gallium-67 is used medically in tumor-seeking agents. The half-life of gallium-67 is 78.2 hours. If you begin with 36.6 mg of this isotope, what mass remains after 190 hours have passed?
2 answers
27g