Asked by fatin

Gallium-67 is used medically in tumor-seeking agents. The half-life of gallium-67 is 78.2 hours. If you begin with 36.6 mg of this isotope, what mass remains after 190 hours have passed?

Answers

Answered by DrBob222
k = 0.693/t<sub>1/2</sub>

Substitute k into the following:
ln(36.6/X) = kt
The only unknown is X. Solve for that.
Answered by Ben
27g
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